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Home/ Questions/Q 7967959
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T07:00:08+00:00 2026-06-04T07:00:08+00:00

I have this codes def display(s1,s2): l1 = list(s1) l2 = list(s2) l3 =

  • 0

I have this codes

def display(s1,s2):
    l1 = list(s1)
    l2 = list(s2)
    l3 = [None]*10
    for i in range(10):
        for j in range(10):
            if i==l2[j]:
                l3[j] = l1[i]
    return l3

print display('3941068257', '1234567890')

Example: 3 in position 0 of list1; 0 in position 9 of list2 => we will display 3 in position 9 in new list called l3 and so on ….

so program supposes to display like that 9410682573 but it still display None none ……

My compiler doesn’t have debugger so I don’t know how to find out. Anyone can help?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T07:00:09+00:00Added an answer on June 4, 2026 at 7:00 am

    You are comparing string (one-char element of l2) with integer. It always fails.

    It is because the below happens:

    l2 = ['3','9','4','1','0','6','8','2','5','7']  # when you do "l2 = list(s2)"
    for i in [0,1,2,3,4,5,6,7,8,9]:  # when you do "for i in raange(10)"
    

    The types just don’t match.

    Instead do this:

    def display(s1,s2):
        l1 = list(s1)
        l2 = list(s2)
        l3 = [None]*10
        for i in range(10):
            for j in range(10):
                if str(i) == l2[j]:  # <-- change is here
                    l3[j] = l1[i]
        return l3
    
    print display('3941068257', '1234567890')
    
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