Question

I have this complicated SQL query for Oracle that I want to visualize in a diagram to make it understandable for my co-workers. I tried at http://snowflakejoins.com but it just chokes on it.

Has someone a better suggestion? I prefer a web-app on the internet and if not a desktop app for windows.

with 
  logs as (
    select 
      l.job_id, 
      l.subjob,
      sum(l.verwerkt) verwerkt, 
      sum(l.errors) errors, 
      max(l.datum) laatst
     from 
      dinf_monitor_logs l, 
      dinf_monitor_jobs j 
     where 
      l.datum>sysdate-j.dagen
      and j.job_id=l.job_id(+)
     group by 
      l.job_id, 
      l.subjob
  ),
  alllogs as (
    select job_id, subjob, max(datum) laatst from dinf_monitor_logs group by job_id, subjob
  )
  select row_number() over(order by alllogs.job_id, alllogs.subjob) r,
    alllogs.job_id,
    alljobs.naam,
    alllogs.subjob,
    logs.verwerkt, 
    logs.errors, 
    alllogs.laatst datum,
    alljobs.wikilink,
    alljobs.loglink,
    alljobs.contact,
    case 
      when alllogs.laatst is null then 1
      when round(sysdate-(alllogs.laatst+alljobs.dagen))<0 then 0
      else round(sysdate-(alllogs.laatst+alljobs.dagen))
    end overtijd,
    case 
      when logs.errors-alljobs.max_errors>0 then 5
      when logs.verwerkt-alljobs.min_verwerkt<0 then 7
      when round(sysdate-(alllogs.laatst+alljobs.dagen))>0 then 3
      else 11
    end status
  from logs, alllogs, (select job_id, naam, wikilink, loglink, contact, dagen, min_verwerkt, max_errors from dinf_monitor_jobs) alljobs
  where 
    logs.job_id(+)=alllogs.job_id 
    and logs.subjob(+)=alllogs.subjob
    and alllogs.job_id=alljobs.job_id
  order by alllogs.job_id, alllogs.subjob

Answer 1

You can use the “Query Builder” tab of the Oracle’s SQL Developer.

The result of your sample query will be: