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Home/ Questions/Q 1005673
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T08:20:09+00:00 2026-05-16T08:20:09+00:00

I have this example code: #include template<class T> class Class { public: typedef boost::shared_ptr<Class<T>

  • 0

I have this example code:
#include

template<class T>
class Class
{
public:
    typedef boost::shared_ptr<Class<T> > Ref;
};

template<class T>
class Class2
{
public:
    Class<T>::Ref getAReference() {return Class<T>::Ref(new Class<T>);};
};
int main(){}

When I try to compile it, I get:

test.cpp:14: error: type ‘Class<T>’ is not derived from type ‘Class2<T>’
test.cpp:14: error: expected ‘;’ before ‘getAReference’

I do not get it, why does it not work? How do I make it work?

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  1. Editorial Team
    Editorial Team
    2026-05-16T08:20:09+00:00Added an answer on May 16, 2026 at 8:20 am

    You need to tell the compiler that Ref is a type by using typename i.e.

    typename Class<T>::Ref getAReference() {return Class<T>::Ref(new Class<T>);};
    

    This question discusses it further.

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