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Home/ Questions/Q 6677595
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:08:28+00:00 2026-05-26T04:08:28+00:00

I have this piece of code: _regex = /((?<!placeholder)\w+(?:\s*=\s*(?:[^]*|'[^’]*’)))/; imgTag = imgTag.replaceAll(_regex, ‘ ‘);

  • 0

I have this piece of code:

_regex = /((?<!placeholder)\w+(?:\s*=\s*(?:"[^"]*"|'[^']*')))/;     
imgTag = imgTag.replaceAll(_regex, ' ');

Have also tried this instead:

imgTag = imgTag.replace( new RegExp( /((?<!placeholder)\w+(?:\s*=\s*(?:"[^"]*"|'[^']*')))/, "gi" ), ' ');

But my code never gets passed this line:

_regex = /((?<!placeholder)\w+(?:\s*=\s*(?:"[^"]*"|'[^']*')))/;     

Or this line:

imgTag = imgTag.replace( new RegExp( /((?<!placeholder)\w+(?:\s*=\s*(?:"[^"]*"|'[^']*')))/, "gi" ), ' ');

So the problem is in my RegEx, right?

I can’t see it, can anyone please shed a light?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:08:29+00:00Added an answer on May 26, 2026 at 4:08 am

    Javascript doesn’t support lookbehinds. You can’t write this:

    (?<!placeholder)
    

    Use a lookahead instead:

    ((?!placeholder).{11}|^.{0,10})
    

    You’ll need to adjust your replacement string too, because this matches extra characters just before the start of what you want to replace.


    Also this won’t work: var regex = new Regexp(/.../, "gi");

    Write this instead: var regex = /.../gi;

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