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Home/ Questions/Q 8584139
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T21:42:08+00:00 2026-06-11T21:42:08+00:00

I have this piece of code that loops 1 through 99 and is a

  • 0

I have this piece of code that loops 1 through 99 and is a formula.

function getExperienceByLevel ($maxLevel)
{
    $levels = array ();
    $current = 0;

    for ($i = 1; $i <= $maxLevel; $i++)
    {
        $levels[$i - 1] = floor ($current / 4);
        $current +=  floor($i+300*pow(2, ($i/9.75)));
    }

    return $levels;
}

First you initiate it like so $aLevels = getExperienceByLevel(99); then to see how much EXP you need to get to level 6 you do this echo $aLevels[5]; since it’s an array.

Now I’m trying to do reverse. Get Level by EXP.

function getLevelByExp($exp) 
{
    $myLevel = 0;
    $aLevels = getExperienceByLevel(99);

    for ($i = 1; $i < 100; $i++)
    {
        if ($exp > $aLevels[$i-1]) 
        { 
            return $myLevel;
        }
    }
}

When called upon getLevelByExp(1124); or any number inside, it seems to return a zero. But it seems to work when you put echos inside that statement.

Like instead of return $myLevel do echo "You are up to level $i<br />"; and it will go all the way up to the current level you’ve gained EXP for.

But still.. doesn’t work when I want to simply return a number.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T21:42:10+00:00Added an answer on June 11, 2026 at 9:42 pm

    This seems to work better than your function:

    function getLevelByExp($exp)
    {
            $aLevels = getExperienceByLevel(99);
            for ($i = 0;  $i <= 99;  ++$i)
            {
                    //echo "cmp $exp >= aLevels[$i]={$aLevels[$i]}\n";
                    if ($exp <= $aLevels[$i])
                            return $i - 1;
            }
            return -1;
    }
    

    It needs improvement for the edge cases, such as when $exp is zero.

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