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Home/ Questions/Q 8151713
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T15:28:30+00:00 2026-06-06T15:28:30+00:00

I have this working: address = [] for row in ws.iter_rows(row_offset=4,column_offset=3): if len(row) >

  • 0

I have this working:

address = []

for row in ws.iter_rows(row_offset=4,column_offset=3):
    if len(row) > 0:
        cell = row[2]
        if cell.internal_value is not None: 
           *something here, append appropriate cell values to address*

print address
return address

Which will successfully go through a column in an excel spreadsheet and get every nonempty cell. At the asterisks, though, I am unsure how to go through the output and pull out only the numbers. I know that might be odd to read through, but the numbers I need are the “1.0, 2.0, 3.0, 4.0, etc”. All of the other parts, and the actual numbers themselves, are subject to change as I read in different spreadsheets, but they will be in the same format.

So what I need to know is how i would go through this list and get rid of everything that isnt a decimal number, and ideally convert those decimals into integers.

Im also sure that there is a good way to do this with list comprehension, but I’ve only been programmning in python for a week so Im not sure how to really do that.

Sorry if this is confusing, and thanks for any help in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-06T15:28:32+00:00Added an answer on June 6, 2026 at 3:28 pm

    You can do this:

    int_values = [int(v) for v in cell.internal_values if type(v) == float]
    

    Or, I noticed that these values are separated by one item, so you might want this too:

    int_values = [int(cell.internal_values[i]) for i in xrange(1, len(cell.internal_values), 2)]
    

    (you might need to use range(1, …) because the first one should be discarded, the pattern starts at index 1).

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