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Home/ Questions/Q 8413495
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T00:55:54+00:00 2026-06-10T00:55:54+00:00

I have two template classes like template <class T> class MyClass1{}; template <class T>

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I have two template classes like

template <class T>
class MyClass1{};

template <class T>
class MyClass2{};

and I have a template function using them as an argument. The classes are specialized with std::string:

template <template class<std::string> T> myMethod(T<std::string>& arg){}

I’d like to use myMethod(objectOfMyClass1) and myMethod(objectOfMyClass2), but the code doesn’t compile. How to specialize a template class for a template function?

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  1. Editorial Team
    Editorial Team
    2026-06-10T00:55:54+00:00Added an answer on June 10, 2026 at 12:55 am

    This is a compilable example

    template <class T>
    class MyClass1{};
    
    template <class T>
    class MyClass2{};
    
    template <template <typename> class T> 
    void myMethod(T<std::string>& arg){}
    
    int main()
    {
    MyClass1<std::string> c1;
    myMethod(c1);
    MyClass1<std::string> c2;
    myMethod(c2);
    }
    
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