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Home/ Questions/Q 3404368
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T05:22:28+00:00 2026-05-18T05:22:28+00:00

I have written the following code: public class NewClass2 implements Comparator<Point> { public int

  • 0

I have written the following code:

public class NewClass2 implements Comparator<Point>
{
    public int compare(Point p1, Point p2)
    {
        return (int)(p1.getY() - p2.getY());
    }
}

If I let’s say have two double numbers, 3.2 - 3.1, the difference should be 0.1. When I cast the number to an int, however, the difference ends up as 0, which is not correct.

I therefore need compare() to return a double, not an int. The problem is, my getX field is a double. How can I solve this problem?

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  1. Editorial Team
    Editorial Team
    2026-05-18T05:22:29+00:00Added an answer on May 18, 2026 at 5:22 am

    You don’t need to return double.

    The Comparator interface is used to establish an ordering for the elements being compared. Having fields that use double is irrelevant to this ordering.

    Your code is fine.

    Sorry, I was wrong, reading the question again, this is what you need:

    public class NewClass2 implements Comparator<Point> {
        public int compare(Point p1, Point p2) {
            if (p1.getY() < p2.getY()) return -1;
            if (p1.getY() > p2.getY()) return 1;
            return 0;
        }    
    }
    
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