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Home/ Questions/Q 4014306
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T09:28:51+00:00 2026-05-20T09:28:51+00:00

I have written this piece of code: namespace { void SkipWhiteSpace(const char *&s) {

  • 0

I have written this piece of code:

namespace {

void SkipWhiteSpace(const char *&s) {
  if (IsWhiteSpace(*s)) {
    s++;
  }
}

bool IsWhiteSpace(char c) {
  return c == ' ' || c == '\t' || c == '\n';
}

} // namespace

The problem is that the compiler complains that IsWhiteSpace() was not declared in this scope. But why? Sure, the namespace is anonymous but still the functions lie within the same namespace, aren’t they?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T09:28:52+00:00Added an answer on May 20, 2026 at 9:28 am

    Perhaps it’s because you’re defining IsWhiteSpace after SkipWhiteSpace.

    Edit:

    I successfully compiled the following code:

    #include <iostream>
    
    using namespace std;
    
    namespace
    {
        void Function2()
        {
            cout << "Hello, world!" << endl;
        }
    
        void Function1()
        {
            Function2();
        }
    }
    
    int main()
    {
        Function1();
    }
    

    Moving Function1 above Function2 results in the error you mentioned. So, yes, it’s because SkipWhiteSpace has no knowledge of IsWhiteSpace. You can solve this by declaring the functions ahead of time and then defining them normally afterwards, like this:

    namespace
    {
        void Function1();
        void Function2();
    
        void Function1()
        {
            Function2();
        }
    
        void Function2()
        {
            cout << "Hello, world!" << endl;
        }
    }
    
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