Question

I have writter code to display result with one image column. somehow it is giving me error

I have written code like this.

<?php $this->widget('zii.widgets.grid.CGridView', array(
'id' => 'photo-grid',
'dataProvider' => $model->search(),
//'filter' => $model,
'columns' => array(
    'id',
    array(
            'name'=>'user_id',
            'value'=>'GxHtml::valueEx($data->user)',
            'filter'=>GxHtml::listDataEx(User::model()->findAllAttributes(null, true)),
            ),
    array(
            'name'=>'regulation_id',
            'value'=>'GxHtml::valueEx($data->regulation)',
            'filter'=>GxHtml::listDataEx(Regulation::model()->findAllAttributes(null, true)),
            ),
    //'photo_img',
    array(
            'name' => 'Photo Img',
            'type' => 'raw',
            'value' => CHtml::image(Yii::app()->controller->createUrl('photo/loadImage', array('id'=>$model->id)),"",array('width'=>50, 'height'=>50)), 
            ),
    array(
        'class' => 'CButtonColumn',
    ),
),

)); ?>

can any one help me how to display image in CGridView?

Answer 1

There is no $model->id on that level

You need to change that into $data, and make sure it is a string, that will be evaluated later when the cell renders (if you leave as non-string, that means it is evaluated before your grid is created)

'value' => 'CHtml::image(Yii::app()->controller->createUrl(\'photo/loadImage\', array(\'id\'=>$data->id)),"",array(\'width\'=>50, \'height\'=>50))',