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Home/ Questions/Q 739715
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:25:57+00:00 2026-05-14T08:25:57+00:00

I hope this code explains the problem: class Foo { void a() { /

  • 0

I hope this code explains the problem:

class Foo {
    void a() { / *stuff */ }
}

class Bar extends Foo {
    void a() { throw new Exception("This is not allowed for Bar"); }

    class Baz {
        void blah() {
            // how to access Foo.a from here?
        }
    }
}

I know that I may be doing something wrong, because inheritance perhaps shouldn’t be used in such way. But it’s the easiest way in my situation. And, beside that, I’m just curious. Is it possible?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:25:58+00:00Added an answer on May 14, 2026 at 8:25 am

    Bar.super.a() appears to work.

    Per JLS section 15.12

    ClassName . super . NonWildTypeArguments_opt Identifier ( ArgumentList_opt )

    is a valid MethodInvocation

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