Question

I just stumbled over the following line of code

cout << &"Blahh" << endl;

The compiler doesn’t give an error and on the console the address is displayed. It works all correctly without any problem. If I replace “Blahh” with an int, so

cout << &10 << endl;

the code won’t compile. For short: a string literal works but an integer literal not.

What is the reason why cout << &"Blahh" << endl; works and cout << &10 << endl; not?

Answer 1

Because "Blahh" has an address in memory (it’s an l-value). 10 doesn’t (it’s an r-value).

http://en.wikipedia.org/wiki/Value_%28computer_science%29