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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T07:02:47+00:00 2026-05-12T07:02:47+00:00

I know that local variables and paramters of methods live in stack, but I

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I know that local variables and paramters of methods live in stack, but I not able to figure out where does actually methods live in case of Java?

If I declare any Thread object like:

Thread t=new Thread();
t.start();

So it means I’ve created a separate calling of methods apart from main method. What does it mean? Does it mean calling of separate sequence of methods over Stack memory? Am I right?

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  1. Editorial Team
    Editorial Team
    2026-05-12T07:02:47+00:00Added an answer on May 12, 2026 at 7:02 am

    Each thread is allocated its own stack.

    This article has a good introduction to the memory separation within a Java process.

    Inside the Java virtual machine, each
    thread is awarded a Java stack, which
    contains data no other thread can
    access, including the local variables,
    parameters, and return values of each
    method the thread has invoked. The
    data on the stack is limited to
    primitive types and object references.
    In the JVM, it is not possible to
    place the image of an actual object on
    the stack. All objects reside on the
    heap.

    I’ve seen many scenarios where clients have implemented hugely threaded servers on the basis that each thread does very little, and they run into problems with memory. That’s because each thread is allocated its own stack, and this (obviously) adds up. I think the default value is 512k per thread, but I’ve not found a canonical source for that.

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