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Home/ Questions/Q 8720223
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:59:09+00:00 2026-06-13T06:59:09+00:00

I know that the following code is not correct, for std::vectors and more generally

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I know that the following code is not correct, for std::vectors and more generally all STL containers:

std::vector<something>::iterator it = array.begin();
for(; it != array.end(); it++) {
   ...
   array.erase(it);
   ...
}

because the iterator needs to be updated after erasing and element.

I was wondering if it’s the same for a boost multi-index, e.g would something like the following be correct or not:

my_index::iterator it = index.get<0>().begin();
for(; it != index.get<0>().end(); it++) {
   ...
   index.erase(it);
   ...
}

I’d like to be sure to understand well the following paragraph of the documentation: http://www.boost.org/doc/libs/1_51_0/libs/multi_index/doc/tutorial/indices.html#guarantees
which seems to state that I can erase without invalidating the iterator. However I’m not sure if because I delete an element, another element that I would be supposed to visit during the iteration could be moved before the current iterator’s position and never be visited (in other words, by erasing some elements during the iteration, am I still sure to go through all the elements?).

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:59:10+00:00Added an answer on June 13, 2026 at 6:59 am

    The paragraph you linked only applies to hashed (unordered) indices. It states that when inserting new elements, hashed index iterators remain valid.

    When erasing, for ordered indices you can always guarantee complete iteration by using the return value from erase:

    for (; it != index.get<0>().end(); ) {
        if (...) it = index.erase(it);
        else ++it;
    }
    

    This will also work for hashed (unordered) indices, as the iteration order is stable over erasing elements.

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