Question

I know that the following two things are the same in c (because of offsets and arrays)

someArray[i]     //ith element of someArray
*(someArray + i) //ith element of someArray

However for structs, the same syntax doesn’t seem to hold up very well…

someStruct[i]->*(someArray + j)   //compiler error
*(someStruct + i)->someArray[j]   //Also compiler error

Is there anyway to use the pointer/offset notation (the second one) to represent elements of a struct?

Answer 1

Assuming someStruct is an array of structs, and someArray is a struct member of array type, then either of these would be valid:

*(someStruct[i].someArray + j)

or

(*(someStruct + i)).someArray[j]

See e.g. http://ideone.com/UtLN2.