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Home/ Questions/Q 6693679
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T06:00:42+00:00 2026-05-26T06:00:42+00:00

I know there has got to be a cleaner more elegant way to do

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I know there has got to be a cleaner more elegant way to do this. I have an array of number in the range [0,1] and want to check which ones are greater than a threshold. I remember there being some syntax to do this nicely. In python I would use something like a lambda function.

p = sigmoid(dot(theta,X));
for i =1:size(p)
   if(p(i)>=0.5)
      p(i)=1
   else
       p(i)=0
   end
end
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  1. Editorial Team
    Editorial Team
    2026-05-26T06:00:43+00:00Added an answer on May 26, 2026 at 6:00 am

    mtrw is on the right track, but it gets even shorter:

    p = (p >= 0.5);
    
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