Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I made a combinational barrel shifter/rotator. Now I have to make an edge triggered one. If you use the control signals to tell the edge-triggered shifter/rotator to shift right by one bit, then if you don’t change the controls, will the output eventually go to 0?
I’m supposed to design it by using a combinational shifter/rotator and a D register. Why is a D register needed?
It doesn’t eventually go to 0, because the output doesn’t get fed back in as an input. A D-register is needed in order to provide sensitivity to the rising edge of the clock since a combinational shifter/rotator isn’t sensitive to it. On the rising edge the D-register will dump whatever it’s holding into the shifter/rotator.