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Editorial Team
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Asked: 2026-06-13T19:14:59+00:00

I need a regex expression for this any number then . and again number

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I need a regex expression for this

any number then . and again number and .

So this is valid

1.3.164.1.2583.15.46
546.598.856.1.68.268.695.5955565

but

5..........
...56.5656

are not valid

I tried patterns like:

pattern = "[0-9](\\.[0-9]?*)?*";
pattern = "[0-9](\\.[0-9]?*)?$";
pattern = "[^0-9\\.]";

but none of these fulfill my requirement. Please help?

My existing code is

String PATTERN="\\d+(\\.\\d+)*";
@Override
public void insertString(int arg0, String arg1, AttributeSet arg2)
{

    if(!arg1.matches(this.PATTERN))
        return;

    super.insertString(arg0, arg1, arg2);
}
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1 Answer

  1. Editorial Team

    Something like this should work:

    (\\d+\\.?)+

    Edit

    Yep, not clear from the description if a final . is allowed (assuming an initial one is not).

    If not:

    (\\d+\\.?)*\\d+ or \\d+(\\.\\d+)* (if that seems more logical)

    Test

    for (String test : asList("1.3.164.1.2583.15.46",
    "546.598.856.1.68.268.695.5955565", "5..........", "...56.5656"))
    System.out.println(test.matches("\\d+(\\.\\d+)*"));

    produces:

    true
true
false
false
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