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Home/ Questions/Q 6155731
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T20:29:06+00:00 2026-05-23T20:29:06+00:00

I need to compute a numeric representation of a string which is bi-direction. For

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I need to compute a numeric representation of a string which is bi-direction. For example, If I have a string “US” I would like an algorithm which when applied to “US” generates a number X (int or long). When another algorithm is applied to X, I want to get “US”. Each string consists of two characters.

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-23T20:29:07+00:00Added an answer on May 23, 2026 at 8:29 pm

    The following does it easily by using DataInputStream and DataOutputStream to read/write to an underlying byte array.

    public static void main(String[] args) {
    
        String original = "US";
        int i = stringToInt(original);
        String copy = intToString(i);
    
        System.out.println("original: "+original);
        System.out.println("i: "+i);
        System.out.println("copy: "+copy);
    
    }
    
    static int stringToInt(String s) {
    
        byte[] bytes = s.getBytes();
    
        if (bytes.length > 4) {
            throw new IllegalArgumentException("String too large to be" +
                        " stored in an int");
        }
    
        byte[] fourBytes = new byte[4];
        System.arraycopy(bytes, 0, fourBytes, 0, bytes.length);
    
        try {
            return new DataInputStream(new ByteArrayInputStream(fourBytes))
                        .readInt();
        } catch (IOException e) {
            throw new RuntimeException("impossible");
        }
    }
    
    static String intToString(int i) {
    
        ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
        try {
            new DataOutputStream(byteArrayOutputStream).writeInt(i);
        } catch (IOException e) {
            throw new RuntimeException("impossible");
        }
    
        return new String(byteArrayOutputStream.toByteArray());
    }
    
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