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Home/ Questions/Q 8778681
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T19:35:27+00:00 2026-06-13T19:35:27+00:00

I need to compute an expression which looks like: A*B – C*D , where

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I need to compute an expression which looks like:
A*B - C*D, where their types are: signed long long int A, B, C, D;
Each number can be really big (not overflowing its type). While A*B could cause overflow, at same time expression A*B - C*D can be really small. How can I compute it correctly?

For example: MAX * MAX - (MAX - 1) * (MAX + 1) == 1, where MAX = LLONG_MAX - n and n – some natural number.

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  1. Editorial Team
    Editorial Team
    2026-06-13T19:35:28+00:00Added an answer on June 13, 2026 at 7:35 pm

    This seems too trivial I guess.
    But A*B is the one that could overflow.

    You could do the following, without losing precision

    A*B - C*D = A(D+E) - (A+F)D
              = AD + AE - AD - DF
              = AE - DF
                 ^smaller quantities E & F
    
    E = B - D (hence, far smaller than B)
    F = C - A (hence, far smaller than C)
    

    This decomposition can be done further.
    As @Gian pointed out, care might need to be taken during the subtraction operation if the type is unsigned long long.


    For example, with the case you have in the question, it takes just one iteration,

     MAX * MAX - (MAX - 1) * (MAX + 1)
      A     B       C           D
    
    E = B - D = -1
    F = C - A = -1
    
    AE - DF = {MAX * -1} - {(MAX + 1) * -1} = -MAX + MAX + 1 = 1
    
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