Question

i need to get filename from file path string. For example, from this string \abc\def\filename.txt i need to get filename.txt

trying to do this with regexp:

$filepath="abc\filename.txt";
$filename = preg_replace("/.+\\/","",$filepath);

but it gives me an error. What regex i should use to solve this?

Answer 1

you should use the function basename instead:

$filepath = 'abc\filename.txt';
$filename = basename($filepath);

edit: important note, you need to use single quotes when you have backslashes in your strings, else escape them properly.

note: this will not work:

$filepath = "abc\filename.txt";
$filename = basename($filepath);

because you’re variable $filepath infact holds:

abc[special char here equalling \f]ilename.txt

another edit:
this regex works too..

$filepath = '\def\abc\filename.txt';
$basename = preg_replace('/^.+\\\\/', '', $filepath);

all that was wrong with your original was that you had double-quotes rather than single, and backslash needs double escaped (\\ rather than \).