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Home/ Questions/Q 1072807
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T20:54:39+00:00 2026-05-16T20:54:39+00:00

I need to hold an array of C strings. Now I know C strings

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I need to hold an array of C strings. Now I know C strings are just an array of chars so essentially what I want is a 2d array of chars. The strings I’m trying to store will also never exceed 6 characters. My plan is to initialize a char array with 50 “string slots” and then if I hit 50 strings reallocate the array’s memory to double it’s capacity. I’ve tried something simple like:

int main() {
    char strings[50][6];
    strings[0] = "test";
    printf("The string is: %s", strings[0]);
    return(0);
}

But, when I go to compile it I get the following error:

test.c: In function ‘main’: test.c:3:
error: incompatible types when
assigning to type ‘char[6]’ from type
‘char *’ test.c:4: warning:
incompatible implicit declaration of
built-in function ‘printf’

Can anyone point in me in the right direction?

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  1. Editorial Team
    Editorial Team
    2026-05-16T20:54:40+00:00Added an answer on May 16, 2026 at 8:54 pm

    strncpy(strings[0], "test", 6); unless your C library has strlcpy(). However if you are going to need to vary the size of the storage, you’re better off using a char ** with malloc(), realloc() and free().

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