Question

I need to pass a character to the line no. 2: First method I tried,

1) unichar dicttxt = [[myword lowercaseString] characterAtIndex:0];

   2) fileName = [[NSBundle mainBundle] pathForResource:dicttxt ofType: @"txt"];

2nd Method I tried,

NSString *dicttxt = [[myword lowercaseString] characterAtIndex:0];

fileName = [[NSBundle mainBundle] pathForResource:dicttxt ofType: @"txt"];

Both method suggest error Make pointer from integer without a cast.

Answer 1

Rather than using a character, use:

NSString *dicttxt = [[myword lowercaseString] substringWithRange:NSMakeRange(0, 1)];
fileName = [[NSBundle mainBundle] pathForResource:dicttxt ofType:@"txt"];

Alternatively (and I forget about this method entirely), the following is functionally equivalent to the above, but more concise:

NSString *dicttxt = [[myword lowercaseString] substringToIndex:1];
fileName = [[NSBundle mainBundle] pathForResource:dicttxt ofType:@"txt"];    

These will work as long as:

1. myword has a length of at least 1.
2. myword does not start with composite characters (i.e. “café” is fine, but “über” might not be).