Question

I need to transform the XML and am having some issues…

Current XML:

<?xml version="1.0" encoding="utf-8"?>
 <Employees>
  <Employee>
   <ManagerFirstName>Joe</ManagerFirstName>
   <ManagerLastName>Schmoe</ManagerLastName>
  </Employee>
 </Employees>

Desired Output:

<?xml version="1.0" encoding="utf-8"?>
 <Employees>
  <Employee>
   <supervisorName>Schmoe, Joe</supervisorName>
  </Employee>
 </Employees>

Current XSL:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" >
  <xsl:template match="/">
    <xsl:apply-templates select="*"/>
  </xsl:template>
  <xsl:template match="node()">
    <xsl:copy><xsl:apply-templates select="node()"/></xsl:copy>
  </xsl:template>
  <xsl:template match="ManagerFirstName">
        <supervisorName>
        <xsl:apply-templates select="node()"/>
        <xsl:value-of  select="/ManagerLastName"/>
        <xsl:text>, </xsl:text>
        <xsl:value-of select="/ManagerFirstName"/>
        </supervisorName>
  </xsl:template>
</xsl:stylesheet>

This is not working and I can not figure it out. The XML it is outputting at the moment looks like this:

<?xml version="1.0" encoding="utf-8"?>
 <Employees>
  <Employee>
   <supervisorName>Joe, </supervisorName>
   <ManagerLastName>Schmoe/ManagerLastName>
  </Employee>
 </Employees>

I feel like I’m so close…

UPDATE
How would I go about making sure that if ManagerFirstName and ManagerLastName are blank, that supervisorName does not have the comma inside of it?

UPDATE 2

<?xml version="1.0" encoding="UTF-8" ?>
 <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output indent="yes"/> <xsl:strip-space elements="*"/>
 <xsl:template match="/">
   <xsl:apply-templates select="*"/>
 </xsl:template>
 <xsl:template match="@*|node()">
   <xsl:copy>
     <xsl:apply-templates select="@*|node()"/>
   </xsl:copy>
 </xsl:template>
 <xsl:template match="Employee">
   <tbl_EmployeeList><xsl:apply-templates select="@*|node()"/></tbl_EmployeeList>
 </xsl:template>
 <xsl:template match="tbl_EmployeeList">
   <xsl:copy>
     <xsl:apply-templates select="@*|node()"/>
       <supervisorName>
         <xsl:value-of select="(ManagerLastName,ManagerFirstName)" separator=", "/>
       </supervisorName>
   </xsl:copy>
 </xsl:template>
</xsl:stylesheet>

Answer 1

You are close. In the ManagerFirstName template you need a slightly different XPath to pull out the last name:

<xsl:template match="ManagerFirstName">
    <supervisorName>
        <xsl:value-of select="../ManagerLastName"/>
        <xsl:text>, </xsl:text>
        <xsl:apply-templates select="node()"/>
    </supervisorName>
</xsl:template>

(the apply-templates is sufficient to give you the value of the ManagerFirstName, you don’t need a specific value-of for that). You then need a no-op template to stop it copying the last name independently

<xsl:template match="ManagerLastName" />

Also note that the usual identity template would match and apply-templates to @*|node() rather than just node() – it makes no difference in your example document because you’re not using any attributes, but if your original XML had attributes then your version of the identity template would drop them.