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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T16:47:12+00:00 2026-05-16T16:47:12+00:00

I often see JavaScript code where a function may take in an options object

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I often see JavaScript code where a function may take in an “options” object and use it like:

var name = typeof options.name !== 'undefined' ? options.name : "Bob";

This seems like it would be equivalent to the following:

var name = options.name || "Bob"; 

Now, I understand that in certain situations you may actually care that options.name is undefined vs null and this makes sense to me, but I often see this in situations where this distinction is not necessary.

I believe I have heard that people write code like this because of some bug in IE. Can someone elaborate please?

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  1. Editorial Team
    Editorial Team
    2026-05-16T16:47:13+00:00Added an answer on May 16, 2026 at 4:47 pm

    I am not aware of the bug in IE, but those statements aren’t exactly equivalent:

    • The first one sets the name variable to the default "Bob" only when options.name is undefined.

    • The second one sets the name variable to "Bob" whenever options.name is falsy. This can be an empty string, the null value, a value of 0, the NaN value, the boolean value false, and also undefined.

    For example, if options.name === 0, the first statement will set the name variable to 0, while the second statement will set it to "Bob".

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