Question

I programmed a validator with JQuery and PHP that works in all browsers except Internet Explorer 9. I get the error message “SCRIPT5: Access denied”.

jQuery code

$('#contact-send').click(function(){
  $.post('functions/db-contact.php',{
    contact_name: $('#contact-name').val(),
    contact_email: $('#contact-email').val(),
    contact_subject: $('#contact-subject').val(),
    contact_message: $('#contact-message').val()
  },
  function(x){
    console.log(x);
  }
});

And this is the response (x):

<?xml version="1.0"?>
<response>
  <mail>
    <name>1</name>
    <email>1</email>
    <subject>1</subject>
    <message>1</message>
    <status>notok</status>
  </mail>
</response> 
SCRIPT5: Access denied

EDIT: I really have no idea what can be the error. I added the DB contact file. @Brad 🙂

<?php
include 'db_login.php';

$name = mysql_escape_string($_POST['contact_name']);
$email = mysql_escape_string($_POST['contact_email']);
$subject = mysql_escape_string($_POST['contact_subject']);
$message = mysql_escape_string($_POST['contact_message']);

echo "<?xml version=\"1.0\"?>\n";
echo "<response>\n";
echo "\t<mail>\n";

$i = 0;
if($name == 'type your name' or $name == '' or strlen(trim($name)) == 0){
  echo "\t\t<name>1</name>\n";
  $i = 1;
}

if($email == 'type your email address' or $email == '' or strlen(trim($email)) == 0){
  echo "\t\t<email>1</email>\n";
  $i = 1;
}

if($subject == 'type subject' or $subject == '' or strlen(trim($subject)) == 0){
  echo "\t\t<subject>1</subject>\n";
  $i = 1;
}

if($message == 'type your message on us' 
  or $message == '' or strlen(trim($message)) == 0){
    echo "\t\t<message>1</message>\n";
    $i = 1;
}

if($i == 1){
  echo "\t\t<status>notok</status>\n";
  echo "\t</mail>\n";
  echo "</response>";
  return false;
}

$sql = "INSERT INTO `d013f578`.`mail` (`id`, `name`, `email`, `subject`, `message`)
       VALUES (NULL, '".$name."', '".$email."', '".$subject."', '".$message."');";
$query = mysql_query($sql) or die;
echo "\t\t<status>ok</status>\n";
echo "\t</mail>\n";
echo "</response>";
?>

Unfortunately I have not found any usable tip on the internet.

Answer 1

So, I have 100% the solution.
Instead jquery 1.8, I’m using jquery 1.6.4 and the problem was thus no longer available!