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Home/ Questions/Q 3228998
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T16:45:33+00:00 2026-05-17T16:45:33+00:00

I ran into this block of code today, and I don’t know how it

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I ran into this block of code today, and I don’t know how it works. I know how to make anonymous classes, but I’m used to seeing a method signature and not just a pair of braces. Is the code between those braces put into a static block? Does it go into the constructor? Or is it something else altogether?

conext.checking(new Expectations() {
    { // <- what does this pair of braces do?
        oneOf(alarm).getAttackAlarm(null);
    }
});
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  1. Editorial Team
    Editorial Team
    2026-05-17T16:45:33+00:00Added an answer on May 17, 2026 at 4:45 pm

    It’s an instance initializer that calls the code within the context of the created object.

    This is equivalent to

    Expectations exp = new Expectations();
    exp.oneOf(alarm).getAttackAlarm(null);
    conext.checking(exp)
    

    Whoever wrote it might have thought he was being more efficient by not declaring a variable (not true) or that it was cleaner code (I disagree).

    The primary place that these initializers are useful like this is when instantiating maps, ie:

    Map map = new HashMap() {{
      put("key1", "value1");   
      put("key2", "value2"); 
    }};
    

    which I think actually is slightly more readable.

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