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Home/ Questions/Q 7540727
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T07:42:35+00:00 2026-05-30T07:42:35+00:00

I suspect this has to do with endianness but I’m not sure how to

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I suspect this has to do with endianness but I’m not sure how to fix it. I have a C++ client telling a Java server how many bytes it’s about to send where the Java server just calls readInt() on the input stream. Then the server goes onto read the rest of the data.

At the moment if the C++ server calls:

char l = '3';
BytesSent = send( Socket, &l, 1, 0 );

Then the corresponding Java side is:

int lBytesSent = m_InDataStream.readInt();

m_AckNack = new byte[lBytesSent];
m_InDataStream.read(m_AckNack)

Bytes lBytesSent tends to be some massive value which then just throws an exception when it comes to creating the array (not surprisingly)

The C++ socket is simply opened up with:

Socket = socket(AF_INET, SOCK_STREAM, 0);
Option = 1000;
setsockopt(Socket, SOL_SOCKET, SO_RCVTIMEO, (char *) &Option, sizeof(Option));
server.sin_family = AF_INET;
server.sin_port = htons(Port);
server.sin_addr.s_addr = INADDR_ANY;
memset(&(server.sin_zero), '\0', 8);
connect(Socket, (sockaddr*)&server, sizeof(server));

And the Java side:

ServerSocket listener = new ServerSocket(port);
Socket server;
server = listener.accept();

Removing the error checking for clarity.

Any suggestions would be great

Many Thanks

Mark

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T07:42:36+00:00Added an answer on May 30, 2026 at 7:42 am

    Try running the number through htonl before sending it (on the C++ side):

    long x = htonl(42); /* x now contains 42 represented in network byte order */
    
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