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Home/ Questions/Q 7872351
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T02:10:46+00:00 2026-06-03T02:10:46+00:00

I tested the variables in the update statement and checked if a database connection

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I tested the variables in the update statement and checked if a database connection is established, however the query doesn’t run, can you please show me the error in my code.

for($i=0; $i <= $numcourses; $i++){
    echo '<div class="new'.$i.'" id="new'.$i.'"><label>'.$course_names[$i].'</label>
    <input name="edit'.$i.'" type="submit" value="Edit" /><input name="delete'.$i.'" type="submit" value="Delete" /><br /></div>';
    $name="edit".$i;    
    if (isset($_POST[$name])){
        echo '<input name="text" type="text" value="'.$course_names[$i].'" /><input name="save'.$i.'" type="submit" value="Save"/>';
    }   
    $name2="save".$i;
    if (isset($_POST[$name2])){
        include "includes/open.php";
            $newname=($_POST['text']);
            $int=$i+1;
            $query = "UPDATE course SET cname = '".$newname."' WHERE cid = '".$int."'";
            mysql_query($query) or die(mysql_error());
            include "includes/close.php";
    }
}

Update: Thanx Marc B, adding or die(mysql_error());showed me the error in my code, everything works again and I’m back on track.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T02:10:48+00:00Added an answer on June 3, 2026 at 2:10 am

    You have no error handling on your query calls:

    mysql_query($query) or die(mysql_error());
                       ^^^^^^^^^^^^^^^^^^^^^^
    

    which would tell you if there’s any problems with the query execution. On a meta level, you’re wide open to SQL injection attacks, so you’d better read up about that and fix the problem before you go any further with your code.

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