Question

I think that this is a fairly simple question… I’ve tried finding the specifics and can’t. The code:

#include <iostream>
using namespace std;

int main() {
    char * veggie_burger = "delicious";
    cout<<endl<<veggie_burger<<endl;
    for (int count = 0; count < 9; count++){
        cout<<veggie_burger[count]
            <<" @: "
            <<&veggie_burger[count]
            <<endl;
    }
    cout<<&veggie_burger;

    return 0;   
}

this will output

delicious
d @ delicious
e @ elicious
l @ licious
i @
icious
c @ cious
i @ ious
o @ ous
u @ us
s @ s
001DF7D4 (or wherever)]

What exactly is the difference between &veggie_burger[n] and &veggie_burger? Shouldn’t the pointer be pointing to the place in memory where &veggie_burger[3] stores ‘l’ and not start the sequence of characters at ‘l’?

Answer 1

veggie_burger[n] is exactly the same as *(veggie_burger+n), so &veggie_burger[n] means veggie_burger + n, or a pointer to the nth character. It has type char*, because it is the address of a character.

&veggie_burger, on the other hand, is the address of the pointer. It has type char **.