I tried running the following code:
double f = 4.35;
int n = (int) (100 * f);
n will be 434. Why?
I tried running the following code: double f = 4.35; int n = (int)
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I tried running the following code:
double f = 4.35;
int n = (int) (100 * f);
n will be 434. Why?
4.35 cannot be represented exactly as a floating-point number since .35 is not a (negative) power of 2. As a result, there’s a bit of roundoff one way or another. There will probably also be roundoff when you multiply by 100. If the resulting number is a bit less than 435, casting to int will take the floor of it, which is 434.
If you’d like to round to the NEAREST integer, you can add 0.5 to the result and then cast to int. This is the most general way to round numbers, although Java has a built-in implementation of rounding.