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Home/ Questions/Q 8548123
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T13:25:18+00:00 2026-06-11T13:25:18+00:00

I try get xml file with this code: HttpWebRequest webReq = (HttpWebRequest)WebRequest.Create(url); HttpWebResponse response

  • 0

I try get xml file with this code:

HttpWebRequest webReq = (HttpWebRequest)WebRequest.Create(url);
HttpWebResponse response = (HttpWebResponse)webReq.GetResponse();
string xml = string.Empty;
using (StreamReader sr = new StreamReader(response.GetResponseStream()))
{
    xml = sr.ReadToEnd();
}

XmlDocument xmlDoc = new XmlDocument();
//xml = xml.Replace((char)(0x1F), ' ');
xmlDoc.LoadXml(xml);

but I get exception as below:

' ', hexadecimal value 0x1F, is an invalid character. Line 1, position 1.

So according to many similar questions on stackoverflow I try add this commented line, but then I get exception:

Data at the root level is invalid. Line 1, position 2.

What’s wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T13:25:19+00:00Added an answer on June 11, 2026 at 1:25 pm

    Assuming the compression that is being applied to the XML is GZip you can uncompress the XML like so:

    HttpWebRequest webReq = (HttpWebRequest)WebRequest.Create(url);
    HttpWebResponse response = (HttpWebResponse)webReq.GetResponse();
    string xml = string.Empty;
    using (GZipStream gzip = new GZipStream(response.GetResponseStream(), CompressionMode.Decompress))
    using (StreamReader sr = new StreamReader(gzip))
    {
      xml = sr.ReadToEnd();
    }
    
    XmlDocument xmlDoc = new XmlDocument();
    //xml = xml.Replace((char)(0x1F), ' ');
    xmlDoc.LoadXml(xml);
    

    If the GZipStream does not work to decompress the XML you’ll have to replace it with the appropriate decompression stream.

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