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Home/ Questions/Q 7648735
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T10:47:30+00:00 2026-05-31T10:47:30+00:00

I try to make an image display in a popup window when a user

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I try to make an image display in a popup window when a user click on it.
The code given below performs this function but after instead of the original page, transition to {server_path/no} “page” occurs. How to avoid this transition?

 <html><head>
<script type="text/javascript">
function show_popup (url,name) {
newpop=window.open(url,name,menubar='no',location='no',scrollbars='yes',resizable='yes');
newpop.focus();
}
</script>

</head>
<body>
<img src=image.jpg height=50 onclick=show_popup("image.jpg","newpop")></img>
</body>
</html>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:47:31+00:00Added an answer on May 31, 2026 at 10:47 am

    I think you need to make a change to ‘location’. try and set it to:

    ..,location='{your image path}',..
    
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