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Home/ Questions/Q 6872321
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:54:47+00:00 2026-05-27T03:54:47+00:00

I use ANTLRWorks for a simple grammar: grammar boolean; // […] lowercase_string : (‘a’..’z’)+

  • 0

I use ANTLRWorks for a simple grammar:

grammar boolean;

// [...]
lowercase_string
        :   ('a'..'z')+ ;

However, the lowercase_string doesn’t match foobar according to the Interpreter (MismatchedSetException(10!={}). Ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:54:47+00:00Added an answer on May 27, 2026 at 3:54 am

    You can’t use the .. operator inside parser rules like that. To match the range 'a' to 'z', create a lexer rule for it (lexer rules start with a capital).

    Try it like this:

    lowercase_string
      :  Lower+ 
      ;
    
    Lower
      :  'a'..'z'
      ;
    

    or:

    lowercase_string
      :  Lower
      ;
    
    Lower
      :  'a'..'z'+
      ;
    

    Also see this previous Q&A: Practical difference between parser rules and lexer rules in ANTLR?

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