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Home/ Questions/Q 6645161
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:15:09+00:00 2026-05-26T00:15:09+00:00

I want to create new variable but name as $class.. For example my $class

  • 0

I want to create new variable but name as $class..
For example my $class is:

array("veriekle","vericek","sayfala");

I want to include there class in my class. (veriekle.class.php,vericek.class.php,etc.). I can this but how can I create new variable.

If “veriekle”.class.php called I want to create new variable as name’s “veriekle”.
This is my class I can include but I can’t create new variable.

Class Database
{
    public function __construct($class)
    {
        foreach($class as $class)
        {
            require_once("sub/" . $class . ".class.php");
        }
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:15:09+00:00Added an answer on May 26, 2026 at 12:15 am
    $$class = new $class();
    

    it is called variable variaable and isn’t recommended, but there it is

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