Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6645161
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T00:15:09+00:00 2026-05-26T00:15:09+00:00

I want to create new variable but name as $class.. For example my $class

  • 0

I want to create new variable but name as $class..
For example my $class is:

array("veriekle","vericek","sayfala");

I want to include there class in my class. (veriekle.class.php,vericek.class.php,etc.). I can this but how can I create new variable.

If “veriekle”.class.php called I want to create new variable as name’s “veriekle”.
This is my class I can include but I can’t create new variable.

Class Database
{
    public function __construct($class)
    {
        foreach($class as $class)
        {
            require_once("sub/" . $class . ".class.php");
        }
    }
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T00:15:09+00:00Added an answer on May 26, 2026 at 12:15 am
    $$class = new $class();
    

    it is called variable variaable and isn’t recommended, but there it is

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I want to create a new variable in javascript but it's name should made
I want to create a new object using Class::DBI. One of the fields of
I want to create an alias for a class name. The following syntax would
Possible Duplicate: Is there a call_user_func() equivalent to create a new class instance? I
Possible Duplicate: Javascript dynamic variable name A very basic question. I want to create
I'm new to PHP so this question seems stupid, but suppose I'm assigning variable
I want to create new node of BeanTreeView, and when I add some node
I'm using Visual Basic 9 (VS2008) I want to create new Tabs as and
I want to create a new net.tcp://localhost:x/Service endpoint for a WCF service call, with
I want to create a new row in my database on a table that

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.