Question

I want to do:

typedef MyTemplateClass<Type01, Type02> TClass;
TClass t;
TClass::InnerClass i;
i.test();

i think the solution could be:

template <typename A, typename B>
class MyTemplateClass
{
public:
    class InnerClass
    {
        //here I can do stuff with A and B
        A test() { return 0; }
    };

    friend class InnerClass;
};

but I want to have ma templates in separate *.inl file included at the bottom of header file

how to define such behaviour in other file?

when i do just

//file.inl
class InnerClass
{
    //here I can do stuff with A and B
    A test() { return 0; }
};

A and B are undefined.

but

template <typename A, typename B>
class InnerClass
{
...
};

makes my method template independent of MyTemplateClass types…

Once again in one sentence:
How to make InnerClass of MyTemplateClass in other file with providing

TClass::InnerClass i;
i.test();

behaviour?

Answer 1

You can’t. In a nutshell. Templates must be wholly defined before instantiation- that means that whatever you do, you’ll have to define the inner class in the template class anyway.