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Home/ Questions/Q 7561581
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T13:11:35+00:00 2026-05-30T13:11:35+00:00

I want to gzip a file hold it in memory and whenever a request

  • 0

I want to gzip a file hold it in memory and whenever a request comes from the client, i want to output the gzipped data. However I get a error 330 message on my browser (i am using the latest version of chrome)

The code below looks straight forward to me, is there something else I am missing?

var http = require('http');
var url = require('url');
var fs = require('fs');
var zlib = require('zlib');
var gzippedData = '';

//read file into memory
fs.readFile('layout.html', function(err, data){
  if(err) throw err;
  zlib.gzip(data, function(err, buffer) {
    if (err) throw err;
    gzippedData = buffer.toString('binary');        
  });
});


var server = http.createServer(function(req, res){
  var path = url.parse(req.url).pathname;
  switch (path){
    case '/': 
        res.writeHead(200, {'content-encoding': 'gzip'});
        res.write(gzippedData);
        res.end();
    break;
    default:  
      res.writeHead(404);
      res.write('404');
      res.end();
}});

server.listen(8080);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T13:11:36+00:00Added an answer on May 30, 2026 at 1:11 pm

    Change

    gzippedData = buffer.toString('binary');        
    

    to

    gzippedData = buffer;
    

    And you should be good to go!

    EDIT: This is because res.write will encode the response as utf8 by default. You could instead change that to res.write(gzippedData, 'binary'), but that’s unnecessary. It’s cheaper to just keep the reference to the buffer instead of allocating a js string and encoding that yet again.

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