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Home/ Questions/Q 6824915
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:57:31+00:00 2026-05-26T21:57:31+00:00

I want to gzip a file in Python. I am trying to use the

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I want to gzip a file in Python. I am trying to use the subprocss.check_call(), but it keeps failing with the error ‘OSError: [Errno 2] No such file or directory’. Is there a problem with what I am trying here? Is there a better way to gzip a file than using subprocess.check_call?

from subprocess import check_call

def gZipFile(fullFilePath)
    check_call('gzip ' + fullFilePath)

Thanks!!

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:57:31+00:00Added an answer on May 26, 2026 at 9:57 pm

    Try this:

    check_call(['gzip', fullFilePath])
    

    Depending on what you’re doing with the data of these files, Skirmantas’s link to http://docs.python.org/library/gzip.html may also be helpful. Note the examples near the bottom of the page. If you aren’t needing to access the data, or don’t have the data already in your Python code, executing gzip may be the cleanest way to do it so you don’t have to handle the data in Python.

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