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Editorial Team
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Asked: 2026-06-09T09:34:57+00:00

I want to remove all tags from my XML file except a finite number

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I want to remove all tags from my XML file except a finite number of tags, which i am aware of . How can i do that with XSLT.

I know i can use the following to strip div tags from my xml but i want to negate, like Strip all BUT Div.

  <xsl:template match = "div">
        <xsl:apply-templates select="@*|node()"/>
  </xsl:template>

More Snippet of the XSLT file:

  <xsl:template match="div"> <!-- switch the element name -->
    <xsl:element name="newdiv">
      <xsl:copy-of select="@*" />
      <xsl:apply-templates />
    </xsl:element>
  </xsl:template>

  <xsl:template match="div"/>
  <xsl:template match="*"> 
     <xsl:copy> 
    <xsl:apply-templates select="@*|node()"/> 
     </xsl:copy> 
  </xsl:template>
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1 Answer

  1. Editorial Team

    I believe this question was answered already.
    Use two templates.

    <xsl:template match="*">
   <!-- Everything -->
</xsl:template>

<xsl:template match="something | somethingelse">
   <!-- what you want ignored -->
</xsl:template>

    Fourth edit.

    Input sample:

    <body>
    <table>
        <tr>
            <td>
            </td>
        </tr>
    <div>content</div>
    </table>
    <div>content again</div>
</body>

    XSLT transformation to do what you need:

    <?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:template match="div">
       <xsl:element name="div">
         <xsl:copy-of select="@*" />
         <xsl:apply-templates />
       </xsl:element>
    </xsl:template>


    <xsl:template match="*">
      <xsl:apply-templates select="@*|node()"/>
    </xsl:template>
</xsl:stylesheet>

    This REMOVES ALL TAGS EXCEPT DIV. And KEEPS ALL TAG CONTENT. I just tried it.

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