Question

I want to run a PHP file via Task Scheduler on Windows.
Everything runs except a parameter comes in.

This runs:

cmd /C C:\php\php.exe
“C:\cron\cronrun.php” >>
“C:\cron\log\cronrun.log” 2>&1

This is not running:

cmd /C C:\php\php.exe
“C:\cron\cronrun.php” –run >>
“C:\cron\log\cronrun.log” 2>&1

How can I run a job which includes an argument?

Thanks for help.
-lony

Sources:

• Set PHP cron job on windows server 2003
• http://richarddingwall.name/2009/01/26/capture-the-output-from-a-scheduled-task/

Answer 1

Try adding -- before the --run like this:

cmd /C C:\php\php.exe "C:\cron\cronrun.php" -- --run >> "C:\cron\log\cronrun.log" 2>&1

The clue is in the usage message:

$ php --help
Usage: php [options] [-f] <file> [--] [args...]

...

  args...          Arguments passed to script. Use -- args when first argument
                   starts with - or script is read from stdin