Question

i want to solve this equation…

 | 1     1     1 | |b0| |exp(t)  |
 | 0     1     2 | |b1|=|exp(t)  |
 | 1     1     1 | |b2| |exp(2*t)|

i like the answer be like this:

for example:

b0=2*exp(t)+exp(2*t)
b1=exp(t)+1
b2=exp(

Answer 1

That matrix is singular, so there’s no unique solution (depending on t, there may be zero or infinitely many solutions). I will replace it with an invertible matrix to demonstrate the method:

>> A = [1,1,1;0,1,2;1,1,0]

A =

     1     1     1
     0     1     2
     1     1     0

After that, solving is a straightforward use of the symbolic capability:

>> t = sym('t');
>> rhs = [exp(t);exp(t);exp(2*t)]

rhs =

   exp(t)
   exp(t)
 exp(2*t)
>> b = A\rhs

b =

   exp(t) - exp(2*t)
 2*exp(2*t) - exp(t)
   exp(t) - exp(2*t)