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Home/ Questions/Q 4574494
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T19:55:50+00:00 2026-05-21T19:55:50+00:00

I want to use templates to reverse the different sequences of XML; For example

  • 0

I want to use templates to reverse the different sequences of XML;
For example :

<book title="Definitive XML Schema">
  <author first="Priscilla" />
  <chapter title="[I] ">
    <section title="[I.1]" />
    <section title="[I.2]">
      <section title="[I.2.1]" />
      <section title="[I.2.2]" />
    </section>
    <section title="[I.3] ">
      <section title="[I.3.1]" />
    </section>
  </chapter>
  <chapter title="[II]">
    <section title="[II.1]" />
    <section title="[II.2]">
      <section title="[II.2.1]" />
      <section title="[II.2.2]" />
    </section>
  </chapter>
</book>

I want to get the output like this:this is my xsl.

<?xml version="1.0" encoding="UTF-8"?>
<book title="Definitive XML Schema">
   <author first="Priscilla"/>
   <chapter title="[I]">
      <section title="[I.3]">
         <section title="[I.3.1]"/>
      </section>
      <section title="[I.2]">
         <section title="[I.2.2]"/>
         <section title="[I.2.1]"/>
      </section>
      <section title="[I.1]"/>
   </chapter>
   <chapter title="[II]">
      <section title="[II.2]">
         <section title="[II.2.2]"/>
         <section title="[II.2.1]"/>
      </section>
      <section title="[II.1]"/>
   </chapter>
</book>

Yes,the sections have been reversed but the chapters are not.

I try to use two templates to solve it,but it can not work..

<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs">
<xsl:output method="xml"  version="1.0" encoding="UTF-8" indent ="yes"/>
 <xsl:template match="/">
 <xsl:apply-templates/>
 <xsl:text>&#10;</xsl:text>
 </xsl:template>

<xsl:template match="book">
  <xsl:copy>
  <xsl:sequence select="@title"/>
  <xsl:sequence select="author"/>
  <xsl:apply-templates select="chapter">
    <xsl:with-param name="seq" select="section"/>

     </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>

 <xsl:template match ="chapter|section" as="element()">
  <xsl:param name="seq" as="element(section)*"/>
   <xsl:copy>
     <xsl:sequence select="@title"/>
     <xsl:if test="not(empty($seq))">
    <xsl:apply-templates select="chapter">
        <xsl:with-param name="seq" select="$seq[position()>1]"/>
    </xsl:apply-templates> 
     <xsl:apply-templates select="$seq[1]"/>    
    </xsl:if>
  </xsl:copy>
 </xsl:template>
 </xsl:transform>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T19:55:51+00:00Added an answer on May 21, 2026 at 7:55 pm

    Here is a simpler XSLT 1.0 (and 2.0) solution:

    <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>
    
     <xsl:template match="node()|@*">
      <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
      </xsl:copy>
     </xsl:template>
    
     <xsl:template match="*[section]">
      <xsl:copy>
       <xsl:copy-of select="@*"/>
       <xsl:apply-templates>
         <xsl:sort select="position()"
          data-type="number" order="descending"/>
       </xsl:apply-templates>
      </xsl:copy>
     </xsl:template>
    </xsl:stylesheet>
    

    when this transformation is applied on the following XML document:

    <book title="Definitive XML Schema">
      <author first="Priscilla" />
      <chapter title="[I] ">
        <section title="[I.1]" />
        <section title="[I.2]">
          <section title="[I.2.1]" />
          <section title="[I.2.2]" />
        </section>
        <section title="[I.3] ">
          <section title="[I.3.1]" />
        </section>
      </chapter>
      <chapter title="[II]">
        <section title="[II.1]" />
        <section title="[II.2]">
          <section title="[II.2.1]" />
          <section title="[II.2.2]" />
        </section>
      </chapter>
    </book>
    

    the wanted, correct result (all sequences of section elements reversed) is produced :

    <book title="Definitive XML Schema">
       <author first="Priscilla"/>
       <chapter title="[I] ">
          <section title="[I.3] ">
             <section title="[I.3.1]"/>
          </section>
          <section title="[I.2]">
             <section title="[I.2.2]"/>
             <section title="[I.2.1]"/>
          </section>
          <section title="[I.1]"/>
       </chapter>
       <chapter title="[II]">
          <section title="[II.2]">
             <section title="[II.2.2]"/>
             <section title="[II.2.1]"/>
          </section>
          <section title="[II.1]"/>
       </chapter>
    </book>
    
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