Question

I want to write a function in class, using the operator that I’ve defined it later before in that class.But I don’t know how to show the operator that now you must use the values of YOUR (x,y).
(I saw someone used $this->func_name in php. but here I don’t know.

class Point
{
  public:

    int x;
    int y;

    bool operator==(Point p)
    {
        if (x == p.x && y == p.y)
            return 1;
        return 0;
    }

    bool searchArea(vector <Point> v)
    {
        for (int i = 0; i < v.size(); i++)
            if (v[i] == /* what ?? */  )
                return 1;
        return 0;
    }
};

int main()
{
    //...
.
.
. 
    if (p.searchArea(v))
       //...
}

Answer 1

I’ve seen two ways:

 if ( *this == v[i] )
 if ( operator==(v[i]) )

this is a pointer to the current object. *this is a reference to the current object. Since the comparison operator takes a reference, you have to dereference the this pointer. Or you can just call the member function directly, which passes this implicitly.