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Home/ Questions/Q 4101320
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T20:40:54+00:00 2026-05-20T20:40:54+00:00

I want to write a function that splits lists into sublists according to what

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I want to write a function that splits lists into sublists according to what items satisfy a given property p. My question is what to call the function. I’ll give examples in Haskell, but the same problem would come up in F# or ML.

split :: (a -> Bool) -> [a] -> [[a]]  --- split lists into list of sublists

The sublists, concatenated, are the original list:

concat (split p xss) == xs

Every sublist satisfies the initial_p_only p property, which is to say (A) the sublist begins with an element satisfying p—and is therefore not empty, and (B) no other elements satisfy p:

initial_p_only :: (a -> Bool) -> [a] -> Bool
initial_p_only p [] = False
initial_p_only p (x:xs) = p x && all (not . p) xs

So to be precise about it,

all (initial_p_only p) (split p xss)

If the very first element in the original list does not satisfy p, split fails.

This function needs to be called something other than split. What should I call it??

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  1. Editorial Team
    Editorial Team
    2026-05-20T20:40:55+00:00Added an answer on May 20, 2026 at 8:40 pm

    I believe the function you’re describing is breakBefore from the list-grouping package.

    Data.List.Grouping: http://hackage.haskell.org/packages/archive/list-grouping/0.1.1/doc/html/Data-List-Grouping.html

    ghci> breakBefore even [3,1,4,1,5,9,2,6,5,3,5,8,9,7,9,3,2,3,8,4,6,2,6]
    [[3,1],[4,1,5,9],[2],[6,5,3,5],[8,9,7,9,3],[2,3],[8],[4],[6],[2],[6]]
    
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