I was recently going through some code and considering whether I need to be careful with the expressions placed inside Debug.Assert statements, such as expensive operations or those with side effects. However, it appears the compiler is pretty smart about completely removing the Assert statement and inner expressions.
For example, the following will only print on debug builds:
static void Main(string[] args)
{
Debug.Assert(SideEffect());
}
private static bool SideEffect()
{
Console.WriteLine("Side effect!");
return true;
}
And this will complain that o is being used before initialization on release builds:
static void Main(string[] args)
{
object o;
Debug.Assert(Initialize(out o));
o.ToString();
}
private static bool Initialize(out object o)
{
o = new object();
return true;
}
It even seems to stand up to expressions such as this (printing “After” in both cases):
static void Main(string[] args)
{
if (false) Debug.Assert(true);
Console.WriteLine("After");
}
I was a little suprised with how smart the compiler is here and its ability to correctly detect cases when the Debug.Assert is removed. So, it got me curious..
- How exactly is the statement removed? The expression tree must be built before the statement is removed in order to properly execute the above
ifstatement correctly. - Is the
System.Diagnostics.Debugclass special here, or is it possible to build your own methods with similar handling? - Are there any ways to “trick” the preprocessor here? Even better, are there situations that one might encounter in real-world code where this could be problematic?
Debug.Assertis declared withConditionalAttribute; as the documentation states, this “[i]ndicates to compilers that a method call or attribute should be ignored unless a specified conditional compilation symbol is defined.”The C# compiler has specific support for that attribute and removes the Debug.Assert during release builds, so it is never part of the built expression tree.
If you right-click on one of your
Debug.Assertstatements, you should be able to go to the definition. Visual Studio will show you “code” generated from the metadata, and there you can see the[Conditional("DEBUG")]attribute applied. So this code is only respected whenDEBUGis#define‘d as part of your build.