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Home/ Questions/Q 6606303
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:22:54+00:00 2026-05-25T19:22:54+00:00

I was trying out the following C code: void main() { int i; for(i

  • 0

I was trying out the following C code:

void main()
{
   int i;
   for(i = 0; i< 10; i++)
   { 
      int num;
      printf("\nthe variable address is: %p", &num);

   }
   getch();
}

I had expected it to either throw an error or declare num multiple times but instead, the output shows the same value for &num, for all the iterations of the for loop.
What is the reason behind this behavior? It seems that irrespective of having the declaration in the for loop, the actual declaration/definition happens just once.

Can someone help me understand this behavior?

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:22:54+00:00Added an answer on May 25, 2026 at 7:22 pm

    To help illustrate this, compare this:

       int i;
       int val = 0;
       for(i = 0; i< 5; i++)
       { 
          int num = val++;
          printf("\nthe variable address is: %p", &num);
          printf("\nthe value is: %d", num);
       }
    

    This again shows that num always has the same address, but also is initialised with a distinct value each iteration.

    The idea with the stack is that its layout is defined at compile time; each stack variable maps to an address on the stack with the stack frame.

    Another thing to hlep you get this is to consider that if each iteration “allocated” a new variable, how would a small machine handle a large loop?

    See: Call Stack

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