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Home/ Questions/Q 8640397
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T11:16:13+00:00 2026-06-12T11:16:13+00:00

I would like to instantiate a class in CUDA code, that shares some of

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I would like to instantiate a class in CUDA code, that shares some of its members with other threads in the same block.

However, when trying to compile the following code, I get the error:

attribute "shared" does not apply here

(nvcc version 4.2).

class SharedSomething {

public:
    __shared__ int i; // this is not allowed
};

__global__ void run() {

    SharedSomething something;
}

What is the rationale behind that? Is there a work-around to achieve the desired behavior (shared members of a class across one block)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T11:16:15+00:00Added an answer on June 12, 2026 at 11:16 am

    Rost explained the rationale behind the limitation. To answer the second part of the question, a simple workaround is to have the kernel declare the shared memory, and initialize a pointer to it owned by the class, e.g. in the class constructor. Example.

    class Foo 
    {
    public:
      __device__
      Foo(int *sPtr) : sharedPointer(sPtr, gPtr) {
        sharedPointer[threadIdx.x] = gPtr[blockIdx.x * blockDim.x + threadIdx.x];
        __syncthreads();
      }
    
      __device__
      void useSharedData() { printf("my data: %f\n", sharedPointer[threadIdx.x]); }
    
    private:
      int *sharedPointer;
    };
    
    __global__ void example(int *gData) 
    {
      __shared__ int sData[BLOCKDIM];
    
      Foo f(sData, gData);
    
      f.useSharedData();
    }
    

    Caveat: code written in browser, unverified, untested (and it’s a trivial example, but the concept extends to real code—I have used this technique myself).

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