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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T20:49:55+00:00 2026-05-30T20:49:55+00:00

I would like to transform 42 (Base 10) into 000002A (Base 16) in Erlang…

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I would like to transform 42 (Base 10) into 000002A (Base 16) in Erlang…

I have found some pointers on the web :

io:format("~8..0B~n", [42]) -> 00000042

And

io:format("~.16B~n", [42]) -> 2A

But I cannot seems to find how to do both at the same time, I have tried :

io:format("~8..0.16B~n", [42])

Which seemed to be the logical thing, but it is not, it gives me an error.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-30T20:49:56+00:00Added an answer on May 30, 2026 at 8:49 pm

    io:format(“~8.16.0B~n”, [42]).
    0000002A

    basically, it’s ~F.P.Pad where:

    • F = field width
    • P = precsion
    • Pad = pad character

    see the full io:format docs

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