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Home/ Questions/Q 8807929
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T02:29:26+00:00 2026-06-14T02:29:26+00:00

I wrote a script that gets load and mem information for a list of

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I wrote a script that gets load and mem information for a list of servers by ssh’ing to each server. However, since there are around 20 servers, it’s not very efficient to wait for the script to end. That’s why I thought it might be interesting to make a crontab that writes the output of the script to a file, so all I need to do is cat this file whenever I need to know load and mem information for the 20 servers. However, when I cat this file during the execution of the crontab it will give me incomplete information. That’s because the output of my script is written line by line to the file instead of all at once at termination. I wonder what needs to be done to make this work…

My crontab:

* * * * * (date;~/bin/RUP_ssh) &> ~/bin/RUP.out

My bash script (RUP_ssh):

for comp in `cat ~/bin/servers`; do
    ssh $comp ~/bin/ca
done

Thanks,

niefpaarschoenen

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  1. Editorial Team
    Editorial Team
    2026-06-14T02:29:27+00:00Added an answer on June 14, 2026 at 2:29 am

    You can buffer the output to a temporary file and then output all at once like this:

    outputbuffer=`mktemp` # Create a new temporary file, usually in /tmp/
    trap "rm '$outputbuffer'" EXIT # Remove the temporary file if we exit early.
    for comp in `cat ~/bin/servers`; do
        ssh $comp ~/bin/ca >> "$outputbuffer" # gather info to buffer file
    done
    cat "$outputbuffer" # print buffer to stdout
    # rm "$outputbuffer" # delete temporary file, not necessary when using trap
    
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